bartlettlily69
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A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6.

131 third

161 sixth

1121 over 12

118

Sagot :

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]

Total possible values for a spinner are 3. So, the probability of getting B, we get

[tex]P(B)=\dfrac{1}{3}[/tex]

Total possible values for a die are 6. So, the probability of getting 6, we get

[tex]P(6)=\dfrac{1}{6}[/tex]

Now, the probability of getting a B and then a 6 is

[tex]P(B,6)=\dfrac{1}{3}\times \dfrac{1}{6}[/tex]

[tex]P(B,6)=\dfrac{1}{18}[/tex]

The required probability is [tex]\dfrac{1}{18}[/tex].

Therefore, the correct option is D.

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