Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Carbon dioxide and water react to form methanol and oxygen, like this:

2CO2(g) + 4H2O(g) → 2CH3OH(l) + 3O2 (g)

At a certain temperature, a chemist finds that a 7.5L reaction vessel containing a mixture of carbon dioxide, water, methanol, and oxygen at equilibrium has the following composition:

Compound Amount
CO2 3.28g
H2O 3.86g
CH3OH 1.51g
O2 2.80g

Required:
Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Sagot :

maacastrobr

Answer:

24x10³

Explanation:

2CO₂(g) + 4H₂O(g) → 2CH₃OH(l) + 3O₂ (g)

The equilibrium constant for this reaction is:

Kc = [tex]\frac{[O_2]^3}{[CO_2]^2[H_2O]^4}[/tex]

The expression of [CH₃OH] is left out as it is a pure liquid.

Now we convert the given masses of the relevant species into moles, using their respective molar masses:

  • CO₂ ⇒ 3.28 g ÷ 44 g/mol = 0.0745 mol CO₂
  • H₂O ⇒ 3.86 g ÷ 18 g/mol = 0.214 mol H₂O
  • O₂ ⇒ 2.80 g ÷ 32 g/mol = 0.0875 mol O₂

Then we calculate the concentrations:

  • [CO₂] = 0.0745 mol / 7.5 L = 0.0099 M
  • [H₂O] = 0.214 mol / 7.5 L = 0.0285 M
  • [O₂] = 0.0875 mol / 7.5 L = 0.0117 M

Finally we calculate Kc:

  • Kc = [tex]\frac{0.0117^3}{0.0099^2*0.0285^4}[/tex] = 24x10³

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.