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A projectile is fired upward from the ground with an initial velocity of 300 feet per second. Neglecting air resistance, the height of the projectile at any time t can be described by the polynomial function P(t) = ­16t 2 + 300t

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kirbyateland

Answer: The polynomial that describes the projectile's height is:

P(t) = - ­16t*2 + 300t

For t = 1 second we have:

P(1) = - 16*1^2 + 300*1

P(1) = 284 ft

The height of the projectile after 1 second is 284 feet.

Step-by-step explanation:

The height should be 284 feet.

Given that,

  • A projectile is fired upward from the ground with an initial velocity of 300 feet per second
  • Neglecting air resistance, the height of the projectile at any time t can be described by the polynomial function P(t) = ­[tex]16t \times 2 + 300t[/tex]

Based on the above information, the calculation is as follows:

[tex]P(t) = -16t\times 2 + 300t[/tex]

Here t = 1  

[tex]P(1) = - 16\times 1^2 + 300\times 1[/tex]

= 284 ft

Learn more: brainly.com/question/17429689

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