Answer:
Heat capacity, Q = 781.74 Joules
Explanation:
Given the following data;
Mass = 12g
Initial temperature = 28.3°C
Final temperature = 43.87°C
Specific heat capacity of water = 4.184J/g°C
To find the quantity of heat needed?
Heat capacity is given by the formula;
[tex] Q = mcdt [/tex]
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 43.87 - 28.3
dt = 15.57°C
Substituting into the equation, we have;
[tex] Q = 12*4.184*15.57 [/tex]
Q = 781.74 Joules
The heat that should be needed is Q = 781.74 Joules.
Heat capacity should be
= mcdt
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Now
dt = T2 - T1
= 43.87 - 28.3
= 15.57°C
Now
[tex]= 12\times 4.184 \times 15.57[/tex]
= 781.74 joules
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