Applying limits, it is found that the end behavior of the graph is:
B. As [tex]x \rightarrow \infty, h(x) \rightarrow -\infty[/tex], and as [tex]x \rightarrow -\infty, h(x) \rightarrow \infty[/tex].
The function is:
[tex]h(x) = -2x^5 + 8x^4 - 2x^2 + 15[/tex]
To find the end behavior, we apply the limits as x goes to infinity, in which just the term with the highest exponent is considered, hence:
[tex]\lim_{x \rightarrow -\infty} h(x) = \lim_{x \rightarrow -\infty} -2x^{5} = -2(-\infty)^5 = -2(-\infty) = \infty[/tex]
Then, as [tex]x \rightarrow -\infty, h(x) \rightarrow \infty[/tex]
[tex]\lim_{x \rightarrow \infty} h(x) = \lim_{x \rightarrow \infty} -2x^{5} = -2(\infty)^5 = -2(\infty) = -\infty[/tex]
Then, as [tex]x \rightarrow \infty, h(x) \rightarrow -\infty[/tex]
Hence, option B is correct.
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