Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A sample of gas has an initial volume of 15 L and an initial pressure of 4.5 atm. If the pressure changes to 1.8 atm, what is the new volume, assuming that the temperature remains constant?

Sagot :

Answer:

37.5 L

Explanation:

Initial Volume, V1 = 15L

Initial Pressure P1 = 4.5 atm

Final Pressure, P2 = 1.8 atm

Final Volume V2 = ?

The relationship between these variables is given as;

P1V1 = P2V2

V2 = PIV1 / P1

Inserting the values;

V2 = 4.5 * 15 / 1.8

V2 = 37.5 L

Answer: The new volume is 37.5L

Explanation:

The question is solved using the principle and formula of a gas law known as the Boyle's law. Boyle's law states that provided the temperature remains constant, the volume of a given mass of gas is inversely proportional to its pressure. Expressing the statement mathematically:

P ∝ 1/V, (where p is equal to pressure and V is volume)

Therefore PV = a constant

If a gas at pressure P1 and Volume V1 changes at constant temperature to pressure P2 and volume V2 then:

P1V1 = P2V2.

Using the formula to solve the question:

P1 = 4.5atm

P2 = 1.8atm

V1= 15L

V2 = ?

V2 = P1V1/P2

V2= 4.5 × 15 /1.8

V2 = 67.5/1.8

V2 = 37.5 L

Therefore the new volume is 37.5L

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.