Answered

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Write an equation of a linear function with slope −2 that passes through the point (4,−5).

Sagot :

Answer:

y=-2x+3

Step-by-step explanation:

y-y1=m(x-x1)

y-(-5)=-2(x-4)

y+5=-2x+8

y=-2x+8-5

y=-2x+3

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