The pressure at which the volume of the gas is 2 L at the same temperature as when the volume of a gas is 400 mL and pressure 1 atm is 0.2 atm.
According to combined gas law,
[tex]\rm \dfrac{PV}{nT} = R[/tex]
In the Combined Gas Law,if we change either one of the variables the others will also change.
When the moles of the gas is constant , the above equation can be written as ,
[tex]\rm \dfrac{P'V'}{T'} = \dfrac{PV}{T}[/tex]
Given is P = 1 atm , V= 400ml , V'= 2L= 2000ml , P'= ? T=T'
So we will substitute the values in the above formula keeping temperature constant.
[tex]\rm P'V' = PV\\\\\rm P' \times 2000 = 1 \times 400\\ \\\m P'= \dfrac{1\times 400}{2000} = 0.2 \; atm\\\\\rm P' = 0.2 \; atm\\[/tex]
Therefore the pressure at which the volume of the gas is 2 L at the same temperature as when the volume of a gas is 400 mL and pressure is 1 atm is 0.2 atm.
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