witchface2021
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

let f(x) = 2x + 1 and g(x) = x^2+x-2

find (fg)(x) =

Sagot :

Nayefx

Answer:

[tex] \huge \boxed{ \boxed{\sf {2x}^{2} + 2x - 6} }[/tex]

Step-by-step explanation:

to understand this

you need to know about:

  • composite function
  • PEMDAS

tips and formulas:

  • [tex] (f \circ \: g)x \iff \: f(g(x))[/tex]

given:

  • f(x)=2x+1
  • g(x)=x²+x-2

let's solve:

  1. [tex] \sf sustitute \: the \: value \: of \: g(x) \: to \: f(x) : \\ \sf2( {x}^{2} + x - 2) - 2[/tex]
  2. [tex] \sf distribute : \\ \sf 2 {x}^{2} + 2x - 4 - 2[/tex]
  3. [tex] \sf simplify \: substraction : \\ \sf {2x}^{2} + 2x - 6[/tex]

msm555

Answer:

Solution given:

(x) = 2x + 1

and

g(x) = x^2+x-2

now

fg (x)=f( x^2+x-2)= 2( x^2+x-2) + 1=2x²+2x-4+1

=2x²+2x-3 is your answer

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.