witchface2021
Answered

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let f(x) = 2x + 1 and g(x) = x^2+x-2

find (fg)(x) =

Sagot :

Nayefx

Answer:

[tex] \huge \boxed{ \boxed{\sf {2x}^{2} + 2x - 6} }[/tex]

Step-by-step explanation:

to understand this

you need to know about:

  • composite function
  • PEMDAS

tips and formulas:

  • [tex] (f \circ \: g)x \iff \: f(g(x))[/tex]

given:

  • f(x)=2x+1
  • g(x)=x²+x-2

let's solve:

  1. [tex] \sf sustitute \: the \: value \: of \: g(x) \: to \: f(x) : \\ \sf2( {x}^{2} + x - 2) - 2[/tex]
  2. [tex] \sf distribute : \\ \sf 2 {x}^{2} + 2x - 4 - 2[/tex]
  3. [tex] \sf simplify \: substraction : \\ \sf {2x}^{2} + 2x - 6[/tex]

msm555

Answer:

Solution given:

(x) = 2x + 1

and

g(x) = x^2+x-2

now

fg (x)=f( x^2+x-2)= 2( x^2+x-2) + 1=2x²+2x-4+1

=2x²+2x-3 is your answer

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