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find the distance between each pair of parallel lines with the guven equation y=3x+12 y=3x-18​

Sagot :

clarch19

Answer:

18

Step-by-step explanation:

first line crosses y-axis at 12 and second line crosses y-axis at -18; therefore, distance is 30

abidemiokin

The distance between each pair of parallel lines with the given equation y=3x+12 and y=3x-18​ is 30 units

In order to get the required distance, we will first get the y-intercept of each line.

The standard equation of a line is expressed as y = mx + b

m is the slope of the line

b is the y-intercept;

Given the equation y = 3x + 12

Compared with the general equation;

b = 12

Similarly for y = 3x - 18

b = -18

The difference between the y intercept will be the required distance;

d = 12 - (-18)

d = 12 + 18

d = 30 units

Hence the distance between each pair of parallel lines with the given equation y=3x+12 and y=3x-18​ is 30 units

Learn more here: https://brainly.com/question/17888907

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