Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
300 centavos
Explanation:
De la pregunta anterior, se obtuvieron los siguientes datos:
Potencia (P) = 2500 W
Tiempo (t) = 8 horas
Costo de operación =?
A continuación, convertiremos 2500 W a KW. Esto se puede obtener de la siguiente manera:
1000 W = 1 KW
Por lo tanto,
2500 W = 2500 W × 1 KW / 1000 W
2500 W = 2,5 KW
Por tanto, 2500 W equivalen a 2,5 KW
A continuación, determinaremos la energía consumida. Esto se puede obtener de la siguiente manera: Potencia (P) = 2,5 KW
Tiempo (t) = 8 horas
Energía (E) =?
E = Pt
E = 2,5 × 8
E = 20 KWh
Finalmente, determinaremos el costo de operación. Esto se puede obtener de la siguiente manera:
1 KWh = 15 centavos
Por lo tanto,
20 KWh = 20 KWh × 15 centavos / 1 KWh
20 KWh = 300 centavos
Por lo tanto, costará 300 centavos tener un radiador de 2500 W encendido toda la noche (8 horas).
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.