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-8× + 40 >-16 please help​

Sagot :

Answer:

hi

Step-by-step explanation:

[tex] - 8x + 40 > - 16 \: \: \: \: \: add \: - 40 \: to \: both \: sides \\ \\ - 8x + 40 - 40 > - 16 - 40 \\ - 8x > - 56 \\ divide \: both \: sides \: on \: - 8 \: and \: change \: the \: sign \\ \\ x < \frac{ - 56}{ - 8 } \\ x < 7[/tex]

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