jasleue
Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

There are 107 coins in a jar, all dimes and nickels. The coins are worth $6.70. How many of each kind of
coin is in the jar?


Sagot :

LammettHash

d = number of dimes

n = number of nickels

The jar contains a total of 107 coins, so

d + n = 107

Each dime is worth $0.10 and each nickel is worth $0.05, and the jar contains a total value of $6.70, so

0.10d + 0.05n = 6.70

Multiply both sides of the second equation by 100 to eliminate the decimal points:

10d + 5n = 670

Multiply both sides of the first equation by -5:

-5d - 5n = -535

Add the corresponding sides of these two equations to eliminate n and solve for d :

(10d + 5n) + (-5d - 5n) = 670 + (-535)

(10 - 5)d + (5 - 5)n = 670 - 535

5d = 135

d = 135/5 = 27

Then

n = 107 - d = 80

so the jar contains 27 dimes and 80 nickels.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.