Ttrewarrior
Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A single 6 side die is 'rolled twice. There are 36 equally likely outcomes.
Find the probability of getting two numbers whose sum is
8.The probability of getting two numbers whose sum is 8 is

Sagot :

Answer:

Your first answer is in picture:

8. The possible outcomes when two dice are thrown together are:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).

Therefore, the number of possible outcomes when two dice are thrown is 36.

Now, the possible outcomes of getting a sum equal to 8 is {(2,6),(3,5),(4,4),(5,3),(6,2)}, which means the number of favourable outcome is 5.

Therefore, probability P of getting a sum equal to 8 is:

P= 36/5

Hence, the probability of getting a sum equal to 8 is 36/5 .

Step-by-step explanation:

Hope it is helpful...

View image Аноним
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.