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A ball is thrown upward from a height of 15 feet with an initial upward velocity of 5 feet per second. Use the formula b(t)= -16t2 + 5t + 15 to find the time it takes for the ball to reach the maximum height of the ball. Round to the nearest tenth.

Sagot :

Answer:

Time taken by the ball to reach the maximum height = 5/32 seconds

Step-by-step explanation:

To find the time at which maximum height is reached , we will differentiate the given equation  with respect to t

[tex]\frac{db_{(t)}}{dt} = -32t + 5 = 0\\t = \frac{5}{32} \\[/tex]

Substituting this value of t in formula of b(t), we get

[tex]-16 * (\frac{5}{32})^2 + 5 * \frac{5}{32} + 15 \\= 15.390[/tex]

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