Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A ball is thrown upward from a height of 15 feet with an initial upward velocity of 5 feet per second. Use the formula b(t)= -16t2 + 5t + 15 to find the time it takes for the ball to reach the maximum height of the ball. Round to the nearest tenth.

Sagot :

Answer:

Time taken by the ball to reach the maximum height = 5/32 seconds

Step-by-step explanation:

To find the time at which maximum height is reached , we will differentiate the given equation  with respect to t

[tex]\frac{db_{(t)}}{dt} = -32t + 5 = 0\\t = \frac{5}{32} \\[/tex]

Substituting this value of t in formula of b(t), we get

[tex]-16 * (\frac{5}{32})^2 + 5 * \frac{5}{32} + 15 \\= 15.390[/tex]