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The parallelograms have a combined area of 3 1/7 square yards. The height of each parallelogram is 1 2/7 yards. How long is the base of each parallelogram? What is the area of the smallest rectangle of wall that the mirror could fit on?

Sagot :

Answer:

a) How long is the base of each parallelogram?

1 2/9 yards.

b) What is the area of the smallest rectangle of wall that the mirror could fit on?

3 Square yards

Step-by-step explanation:

The parallelograms have a combined area of 3 1/7 square yards. The height of each parallelogram is 1 2/7 yards.

Step 1

We find the area of each of the parallelogram

This is calculated as:

Combined area of the parallelograms ÷ 2

= 3 1/7 square yards ÷ 2

= 22/7 square yards ÷ 2

= 22/7 square yards × 1/2

= 11/7 square yards

= 1 4/7 square yards.

Step 2

How long is the base of each parallelogram?

The height of each parallelogram is 1 2/7 yards.

Area of parallelogram = Base × Height

Base of each parallelogram = Area of each parallelogram/Height of each parallelogram

= 1 4/7 square yards ÷ 1 2/7 yards

= 11/7 square yards ÷ 9/7 yards

= 11/7 square yards × 7/9 yards

= 11/9 yards

= 1 2/9 yards.

Step 3

What is the area of the smallest rectangle of wall that the mirror could fit on?

Area of a rectangle = Length × Width

Length =(Base of parallelogram × 2)

Width = Base of parallelogram = 1 2/9 yards = 11/9 yards

Length = 1 2/9 yards × 2

= 11/9 × 2 = 22/9 yards

Area of rectangle = 11/9 × 22/9

= 242/81 square yards

= 2.987654321 square yards

Approximately = 3 Square yards

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