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What is the equation of the line perpendicular to y = 1/4x – 5 through the point (4,3)?


Sagot :

y-yi=m(x-xi)

y-3=1/4(x-4)

y-3=x-4/4

4y-12=x-4

4y+x-12+4=0

4y+x-8=0

so the equation of

the line perpendicular

to

y=1/4-5 through

the point(4,3)

is4y-x-8=0