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Sagot :
Answer:
length = 5.38 feet
Step-by-step explanation:
All the eq. can be solved by Phythagoras's theorem
1) Diagonal is 70 inches, height is 42 inches so
70^2 = 42^2 + width^2
width ^2 = 3136, width = 56 inches
2) Base is 2 ft, length of ladder = hypotenuse = 10 ft
Height^2 = 10^2 -2^2 = 96
Height = 9.8 ft
3) Equilateral triangle has a side of 6
If you drop a vertical line from one corner of triangle to opposite side it bisects the side into equal parts. So the length of base is 3
The hypotenuse is 6
So height is sqrt (6*6 -3*3) = sqrt (27) = 3sqrt(3) = 5.2
4) Height = 12, width = 5
Diagonal^2 = 12*12 + 5*5 = 169
Diagonal = 13
5) Plant is 5 ft tall, distance from the ground is 2 ft
length ^2 = 5*5 + 2*2 = 29
length = 5.38 feet
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