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Find the sum of the first 6 terms of the following series, to the nearest integer.
16, 32, 64,...

Sagot :

really226

Answer:

1008

Step-by-step explanation:

geometric sequence:

a=16

r=32/16=2

Sum of GS:

s=a(1-r^n)/(1-r)

S(6)=16(1-2^6)/(1-2)

=1008

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