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A rectangle has perimeter 26 cm, and the length and width are both whole numbers. What is the greatest possible area this rectangle may have in square cm?

Sagot :

The length should be 7 while the breadth should be 6 to maximize the area.

Perimeter of the Rectangle

The perimeter of the rectangle is twice the sum of its length and breadth.

[tex]\rm{Perimeter = 2(length +breadth)[/tex]

Area of the rectangle

the area of the rectangle is given as the product of its length and its breadth.

[tex]\rm{Area ={length\times breadth[/tex]

Given to us

Permeter = 26 cm

Perimeter

[tex]\rm{Perimeter = 2(length +breadth)[/tex]

[tex]26 = 2(length +breadth)[/tex]

[tex]13=(length +breadth)[/tex]

Area of the rectangle

As we know that the area is given as the product of length and breadth. so, we need to find those numbers whose sum is 13. while their product gives us the maximum area.

Therefore, for the area to be maximum the length and breadth should be maximum.

[tex]1 \times 12 = 12\\2\times 11 = 22\\3\times 10 = 30\\4\times 9 = 36\\5\times 8 = 40\\6\times 7 = 42[/tex]

Thus, the length should be 7 while the breadth should be 6 to maximize the area.

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