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Sagot :
Answer:
a = 5 m / s² and x = 562.5 m
Explanation:
Let's apply the kinematics relations
v = v₀ + at
v² = v₀² + 2a x
In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative
0 = v₀ - a t
a = v₀ / t
let's calculate
a = 75/15
a = 5 m / s²
let's look for the distance
0 = v₀² - 2a x
x = v₀² / 2a
let's calculate
x = [tex]\frac{75^2}{2 \ 5 }[/tex]
x = 562.5 m
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