Answered

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4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cuál será la aceleración del frenado? ¿cuál es la distancia que recorre hasta detenerse?

Sagot :

Answer:

a = 5 m / s²   and    x = 562.5 m

Explanation:

Let's apply the kinematics relations

          v = v₀ + at

          v² = v₀² + 2a x

In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative

           0 = v₀ - a t

           a = v₀ / t

let's calculate

           a = 75/15

           a = 5 m / s²

let's look for the distance

           0 = v₀² - 2a x

           x = v₀² / 2a

let's calculate

           x = [tex]\frac{75^2}{2 \ 5 }[/tex]

           x = 562.5 m

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