Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Step-by-step explanation:
n = 52
x bar = 122.31
standard deviation sd = 38.75
1. the hypothesis:
null hypothesis
h0: μ ≤ 35
alternative hypothesis
h1: μ > 35
2.
we have been given the sd of the sample but not that of the population. so what we are supposed to use here is the t test and not the z test. the following conditions have to be met.
- population has to be normal
- sample size has to be more than 30. we have sample size = 52 in this question.
3.
= [tex]\frac{122.31-35}{38.75/\sqrt{52} }[/tex]
= 87.31/5.37
= 16.26
using the T distribution function in excel, the p value was calculated and found to be approximately equal to 0.
TDIST(16.26, 51, 1)
since p value is very small we reject the null and accept the alternate hypothesis.
4. from the result above the answer to this question is yes
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.