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Four processes p0,p1,p2,p3 with burst time as 3,4,2,1 respectively. Use first Come First served. Draw the Gantt chart

Sagot :

Answer:

Please find the Gantt chart in the attachment file.

Explanation:

Given:

[tex]\to P_0 = 3\\\\\to P_1 = 4\\\\\to P_2 = 2\\\\\to P_3 = 1[/tex]

Calculating the average waiting time:

[tex]\to\frac{bust\ time}{ total\ process}[/tex]

  [tex]= \frac{3+4+2+1}{4}\\\\= \frac{10}{4}\\\\= 2.5[/tex]

And the chart is defined in the attached file please find it.

View image codiepienagoya
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