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Given PQ = y, RS = 4y - 15, QR = 2 +6, and PS = 4a - 6, solve for the
length of RS and QR.


Given PQ Y RS 4y 15 QR 2 6 And PS 4a 6 Solve For The Length Of RS And QR class=

Sagot :

Answer:

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Step-by-step explanation:

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