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Sagot :
Answer:
Kindly check explanation
Explanation:
Given the data:
# of accidents per truck per year # of trucks of having this # of accidents
f(X) ____PA Station ____ NJ Station
0 _____ 117 _________ 264
1 _____ 24 __________ 32
2 _____ 9 ____________24
a. What is the random variable illustrated here?
Number of accident per truck per year
b. Calculate the expected value of frequency
per truck in PA station and NJ station, respectively.
Expected value of frequency per truck in PA Station :
Σ(accident per truck * # truck having the accident)
E(x) = Σ(0*117) + (1 * 24) + (2 * 9) = 42
Expected value of frequency per truck in NJ Station :
Σ(accident per truck * # truck having the accident)
E(x) = Σ(0*264) + (1 * 32) + (2 * 24) = 80
c.) Calculated the variance of frequency per truck in the PA station and the NJ station, respectively.
The variance (V) :
Σ(X²*f(x)) - E(x)²
NJ Station :
(0 * 264^2) + (1 * 32^2) + (2 * 24^2) - 42^2
(0 + 1024 + 1152) - 1764
= 412
PA Station:
Σ(0*117^2) + (1 * 24^2) + (2 * 9^2) - 80^2
= (0 + 576 + 162) - 6400
= - 5562
d. PA Station is riskier
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