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A 6.3 μC electric charge is placed in an Electric Field with a magnitude of 5.0 x 105 charge due to the Electric Field? N/C. What is the electric force on the charge due to the electric field

Sagot :

Answer:

F = 3.15 N

Explanation:

Given electric charge, q = 6.3 μC

The magnitude of electric field, [tex]E=5\times 10^5\ N/C[/tex]

We need to find the electric force on the charge due to the electric field. The electric force is given by :

F = qE

Putting all the values,

[tex]F=6.3\times 10^{-6}\times 5\times 10^5\\\\F=3.15\ N[/tex]

So, the required force on the charge is 3.15 N.

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