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4 Al + 3 O₂ --> 2 Al2Ol₃ Given 6 moles of aluminum, how many grams of aluminum oxide will be produced?

Sagot :

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Answer:

305.88 g

Explanation:

4 Al + 3 O₂ → 2 Al₂O₃

First, we convert 6 moles of aluminum (Al) into moles of aluminum oxide (Al₂O₃), using the stoichiometric coefficients:

6 mol Al * [tex]\frac{2molAl_2O_3}{4molAl}[/tex] = 3 mol Al₂O₃

Finally we convert 3 moles of aluminum oxide into grams, using its molar mass:

3 mol Al₂O₃ * 101.96 g/mol = 305.88 g

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