Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Solution :
c). [tex]$\vec{F}_A = $[/tex] force applied by Abe
[tex]$\vec{F}_B = $[/tex] force applied by Barry
[tex]$\vec{F}_E = $[/tex] force applied by Eric
[tex]$\vec{F}_R = $[/tex] Resultant force
[tex]$\vec{F}_A $[/tex] in the vector form can be written as :
[tex]$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$[/tex]
[tex]$\vec{F}_B $[/tex] in the vector form can be written as :
[tex]$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$[/tex]
The resultant,
[tex]$\vec{F}_R= \vec{F}_A+\vec{F}_B $[/tex]
[tex]$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$[/tex]
[tex]$=60 \hat i + 60 \hat j$[/tex]
[tex]$|\vec{F}_R| = \sqrt{60^2+60^2}$[/tex]
= 84.853 N
d). As the three forces are in equilibrium, therefore,
[tex]$|\vec F_E| = |\vec F_R|$[/tex]
[tex]$|\vec F_E| =84.853 \ N$[/tex]
e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.
The direction of the resultant force is :
[tex]$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$[/tex]
[tex]$ = \tan ^{-1}\left(\frac{60}{60}\right)$[/tex]
= 45° north east
The direction of the force E is 45° west or 45° south west.

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.