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Sagot :
Given:
In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80.
To find:
The ratio which represents the cotangent of ∠G.
Solution:
In a right angle triangle, the ratio of the cotangent of an angle is
[tex]\cot \theta =\dfrac{Base}{Perpendicular}[/tex]
It is also written as
[tex]\cot \theta =\dfrac{Adjacent}{Opposite}[/tex]
In ΔFGH, the measure of ∠H=90°. So,
[tex]\cot G =\dfrac{HG}{FH}[/tex]
[tex]\cot G =\dfrac{80}{39}[/tex]
Therefore, the ratio for the cotangent of ∠G is [tex]\cot G=\dfrac{80}{39}[/tex].
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