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In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80. What ratio represents the cotangent of ∠G?

Sagot :

Given:

In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80.

To find:

The ratio which represents the cotangent of ∠G.

Solution:

In a right angle triangle, the ratio of the cotangent of an angle is

[tex]\cot \theta =\dfrac{Base}{Perpendicular}[/tex]

It is also written as

[tex]\cot \theta =\dfrac{Adjacent}{Opposite}[/tex]

In ΔFGH, the measure of ∠H=90°. So,

[tex]\cot G =\dfrac{HG}{FH}[/tex]

[tex]\cot G =\dfrac{80}{39}[/tex]

Therefore, the ratio for the cotangent of ∠G is [tex]\cot G=\dfrac{80}{39}[/tex].

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