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Sagot :
total time = upstream time + downstream time
he rowed the same distance both ways.
upstream time = D/4
downstream time = D/6
total time = D/4 + D/6 = 3D/12 + 2D/12 = 5D/12 = 3 hours
D = 3*12/5 = 36/5 or 7.2 miles
where D is the one-way distance. The total distance he rowed is 2*D = 72/5 or 14.4 miles
he rowed the same distance both ways.
upstream time = D/4
downstream time = D/6
total time = D/4 + D/6 = 3D/12 + 2D/12 = 5D/12 = 3 hours
D = 3*12/5 = 36/5 or 7.2 miles
where D is the one-way distance. The total distance he rowed is 2*D = 72/5 or 14.4 miles
Answer:
Fisherman traveled 14.4 miles.
Step-by-step explanation:
A fisherman's downstream speed = 6 mph
and upstream speed = 4 mph
Let the fisherman traveled x miles he travels upstream.
Time spent in travelling x miles = [tex]\frac{x}{4}[/tex] hours [Since time = [tex]\frac{\text{distance}}{\text{speed}}[/tex]]
Similarly when fisherman covers x miles down stream
Time spent in x miles = [tex]\frac{x}{6}[/tex] hours
Now total time in going upstream and downstream is 3 hours then
[tex]\frac{x}{4}+\frac{x}{6}=3[/tex]
x[tex](\frac{3+2}{12})=3[/tex]
[tex](\frac{5x}{12})=3[/tex]
5x = 12×3
5x = 36
x = [tex]\frac{36}{5}=7.2[/tex] miles.
Since fisherman has traveled 2x distance so the answer will be 14.4 miles
Therefore, fisherman traveled 14.4 miles.
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