Answered

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You are presented with a white solid and told that, because of careless labeling, it is not clear whether the substance is mercury(I) nitrate, calcium carbonate, or aluminum nitrate. When you transfer the solid to a beaker and add water, the solid dissolves to give a clear solution. Next, a Na2SO4(aq) solution is added and a white precipitate forms.

Required:
a. What is the identity of the unknown white solid?
b. How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 2.5 M CH3OH?

Sagot :

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Answer:

aluminum nitrate

Explanation:

We already know that calcium carbonate is insoluble in water hence it will not even dissolve in the water.

Mercury(I) nitrate is soluble in water, when sodium sulfate (Na2SO4) is added to mercury(I) nitrate (Hg2(NO3)2), a pale yellow precipitate is formed.

Aluminum nitrate is soluble in water and reacts with Na2SO4(aq) solution according to the reaction, 2Al(NO3)3(aq)+3Na2SO4(aq) ---> Al2(SO4)3(s)+6NaNO3(aq). The precipitate, Al2(SO4)3(s) is a white crystalline hygroscopic solid.

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