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Determine the slope-intercept equation of a line with a slope of 3/2 that passes through (2, -1).

Sagot :

Hrishii

Answer:

[tex] \orange{ \bold{y = \frac{3}{2}x -4 }}[/tex]

Step-by-step explanation:

Slope of line (m) = [tex] \frac{3}{2} [/tex]

Line passes through the points [tex] (2,\:-1)=(x_1, \:y_1)[/tex]

Equation of line in point slope form is given as:

[tex] y-y_1 =m(x-x_1)[/tex]

Plug the values of m, [tex] x_1\: \&\: y_1[/tex] in the above equation, we find:

[tex]y - ( - 1) = \frac{3}{2} (x - 2) \\ \\ y + 1 = \frac{3}{2}x - \frac{3}{2} \times 2 \\ \\ y + 1 = \frac{3}{2}x -3 \\ \\ y = \frac{3}{2}x -3 - 1 \\ \\ \purple{ \bold{y = \frac{3}{2}x -4 }}\\ \\ [/tex]

This is the required equation of line in slope-intercept form.

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