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Solve for x. Assume that lines which appear to be diameters are actual diameters.​

Solve For X Assume That Lines Which Appear To Be Diameters Are Actual Diameters class=

Sagot :

Answer:

x = 7

Step-by-step explanation:

[tex](4x + 2) \degree = 360 \degree - (85 + 40 + 75 + 130) \degree \\ \\ (4x + 2) \degree = 360 \degree - 330 \degree \\ \\ (4x + 2) \degree = 30 \degree \\ \\ 4x + 2 = 30 \\ \\ 4x = 30 - 2 \\ \\ 4x = 28 \\ \\ x = \frac{28}{4} \\ \\ x = 7[/tex]

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