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Sagot :
Answer:
The correct answer is as follows:
Explanation:
In this given question, Maya is a carrier for albinism which express in presence of two copies of a recessive gene and after marriage with Jack she has 4 children among three are normal and one has albinism which suggests that the ratio of the albinism in this family is 3:1 phenotypically.
Maya - Aa (heterozygous carrier)
Jack - AA or Aa
cross between two
A a
A AA Aa
a Aa aa
this cross showing that the jack is heterozygous for the condition as the result are the same as given in question 3:1
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