Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
[tex]P=3.33atm[/tex]
Explanation:
Hello!
In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:
[tex]n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr[/tex]
Next, we add them up to obtain the total moles:
[tex]n_T=0.981mol+0.654mol=1.635mol[/tex]
Now, the total volume:
[tex]V_T=4.00L+8.00L=12.00L[/tex]
Finally, the total pressure is computed by using the ideal gas equation:
[tex]P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm[/tex]
Best regards!
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.