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Sagot :
Answer:
(x-7)²+(y-4)²=3²
Step-by-step explanation:
to understand this
you need to know about:
- circle equation
- PEMDAS
tips and formulas:
- circle equation standard form: (x-a)²+(y-b)²=r²
given:
- (a,b)=(7,4)
- r=3
let's solve:
- substitute the values of a,b and r :(x-7)²+(y-4)²=3³
and
we are done
The equation of a circle is a measure of its center and its radius.
The equation of the circle is: [tex]x^2 + y^2 - 14x -8y + 56 = 0[/tex]
The general equation of a circle is [tex](x - a)^2 + (y - b)^2 + r^2[/tex]. Where:
[tex](a,b) \to[/tex] center
[tex]r \to[/tex] radius
From the given figure, we have:
[tex]r = 3[/tex]
[tex](a,b) = (7,4)[/tex]
So, the equation of the circle is:
[tex](x - a)^2 + (y - b)^2 + r^2[/tex]
[tex](x - 7)^2 + (y - 4)^2 = 3^2[/tex]
[tex](x - 7)^2 + (y - 4)^2 = 9[/tex]
Open brackets
[tex]x^2 - 14x + 49 + y^2 -8y + 16 = 9[/tex]
Collect like terms
[tex]x^2 + y^2 - 14x -8y + 49 + 16 - 9 = 0[/tex]
[tex]x^2 + y^2 - 14x -8y + 56 = 0[/tex]
Hence, the equation of the given circle is: [tex]x^2 + y^2 - 14x -8y + 56 = 0[/tex]
Read more about equations of circles at:
https://brainly.com/question/23988015
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