Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
[tex]AC = 9cos(45)[/tex]
[tex]BC = 9 sin(45)[/tex]
Step-by-step explanation:
Given
See attachment for triangle
Required
Select the equations that solves the unknown lengths
From the attachment, the unknown lengths are:
AC and CB
Where
[tex]AB = 9[/tex]
To calculate AC, we make use of cosine rule
[tex]cos\theta = \frac{Adjacent}{Hypotenuse}[/tex]
[tex]cos(45)= \frac{AC}{9}[/tex]
Make AC the subject
[tex]AC = 9*cos(45)[/tex]
[tex]AC = 9cos(45)[/tex]
To solve for BC, we make use of sine rule
[tex]sin\theta = \frac{Opposite}{Hypotenuse}[/tex]
[tex]sin(45)= \frac{BC}{9}[/tex]
Make BC the subject
[tex]BC = 9 * sin(45)[/tex]
[tex]BC = 9 sin(45)[/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.