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Englis
malytic Geometry-Jelksi Anthony
Solving for Side Lengths of Right Triangles
Assignment
Active
Writing Equations Using Trigonometric Ratios
A
Which equations could be used to solve for the
unknown lengths of ABC? Check all that apply.
sin(45%) = BC
45
9
sin(459) = 9
9 tan(45%) = AC
(AC)sin(459) = BC
COS(450) =
С
B

Sagot :

MrRoyal

Answer:

[tex]AC = 9cos(45)[/tex]

[tex]BC = 9 sin(45)[/tex]

Step-by-step explanation:

Given

See attachment for triangle

Required

Select the equations that solves the unknown lengths

From the attachment, the unknown lengths are:

AC and CB

Where

[tex]AB = 9[/tex]

To calculate AC, we make use of cosine rule

[tex]cos\theta = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]cos(45)= \frac{AC}{9}[/tex]

Make AC the subject

[tex]AC = 9*cos(45)[/tex]

[tex]AC = 9cos(45)[/tex]

To solve for BC, we make use of sine rule

[tex]sin\theta = \frac{Opposite}{Hypotenuse}[/tex]

[tex]sin(45)= \frac{BC}{9}[/tex]

Make BC the subject

[tex]BC = 9 * sin(45)[/tex]

[tex]BC = 9 sin(45)[/tex]

View image MrRoyal
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