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Find the surface area of a square pyramid with side length 5 ft and slant height 7 ft.
5 ft
5 ft

Find The Surface Area Of A Square Pyramid With Side Length 5 Ft And Slant Height 7 Ft 5 Ft 5 Ft class=

Sagot :

abidemiokin

Answer:

99.33ft^2

Step-by-step explanation:

The surface area of a square pyramid is expressed as;

TSA = a²+2a√a²/4 + h²

Given that

a = 5ft

h = 7ft

Substitute

TSA = 5²+2(5)√5²/4 + 7²

TSA = 25+10√25/4 + 49

TSA = 25 + 10√(221/4)

TSA = 25 + 10(√55.25)

TSA = 25 + 10(7.433)

TSA = 25 +  74.33

TSA = 99.33ft^2

Hence the surface area of a square pyramid with side length 5 ft and slant height 7 ft is 99.33ft^2

Yoyogr

Answer:5x5=25 fts

4(1/2 x 5ft x7 ft) = 70 fts

Add them up and you get

Answer= 95fts

Step-by-step explanation:

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