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Nitrogen gas reacts with hydrogen gas to produce ammonia according to the following equation.

N2(g)+3H2(g) → 2NH3(g)
What is the mole of ammonia produced from 7.23 x 10−4 moles of the hydrogen reactant, assuming there is sufficient nitrogen to react?


7.23 x 10−47.23 x 10−4

8.42 x 10−38.42 x 10−3

4.82 x 10−44.82 x 10−4

4.83 x 10−3

Sagot :

howyoulikethat

Answer:

4.82 x 10^-4

Explanation:

7.23 x 10^-4 mol H2   l    2 mol NH3

------------------------------------------------------- =  

                                   l    3 mol H2

(7.23 x 10^-4) x 2   /  3 =

4.82 x 10^-4

Hope this helped! ;)

The mole of ammonia produced from 7.23 x 10⁻⁴ moles of the hydrogen reactant when there is sufficient nitrogen to react is 4.82×10⁻⁴.

What is moles?

Moles is a unit which is used to estimate the amount of any substance and it is represented as:
n = W/M , where

W = given mass

M = molar mass

Given chemical reaction is:
N₂(g) + 3H₂(g) → 2NH₃(g)

In the question it is given that sufficient moles of N₂ is present, so the formation of product depends on the moles of H₂. From the stoichiometry of the reaction, it is clear that:

3 moles of H₂ = produce 2 moles of NH₃

7.23×10⁻⁴ moles of H₂ = produce 2/3 × 7.23×10⁻⁴=4.82×10⁻⁴ moles of NH₃

Hence, option (C) is correct i.e. 4.82×10⁻⁴.

To know more about moles, visit the below link:
https://brainly.com/question/1464305

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