Answered

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At what value of x does the graph of the following function F(x) have a
vertical asymptote?

F(x)= 1/x+2

A. 2.
B. -2
C. -1
D. 0

Sagot :

Answer:

B

Step-by-step explanation:

Given

f(x) = [tex]\frac{1}{x+2}[/tex]

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

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