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The half life of a certain tranquilizer in the bloodstream is 36 hours. How long will it take for the drug to decay to 87% of the original dose? Use the exponential decay model to solve.

Sagot :

TheSection

Finding the Decay constant(λ):

λ = 0.693 / (half-life)

we are given that the half-life is 36 hours

λ = 0.693 / (36)

λ = 0.01925 /hour

Time taken for 87% decay:

Since decay is first-order, we will use the formula:

[tex]t = \frac{2.303}{decay constant}log(\frac{A_0}{A} )[/tex]

Where A₀ is the initial amount and A is the final amount

Let the initial amount be 100 mg,

the final amount will be 87% of 100

Final amount = 100*87/100 = 87 mg

Replacing the values in the equation:

[tex]t = \frac{2.303}{0.01925}log(\frac{100}{87} )[/tex]

[tex]t = \frac{2.303}{0.01925}*0.06[/tex]

t = 7.18 hours

We used 'hours' as the unit because the unit of the decay constant is '/hour'

Therefore, the drug will decay to 87% of initial dosage after 7.18 hours

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