ayshafahad343
Answered

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The diagonal of a quadrilateral
shaped field is 16m and the
perpendiculars dropped on it
from the remaining opposite vertices
are 12m and 4m.Find the area of
the field
Please answer and thank you

Sagot :

devishri1977

Answer:

Step-by-step explanation:

Quadrilateral is divided into two triangles

Triangle 1:

Diagonal = 16m , h = 12m

Area1 = [tex]\frac{1}{2}base *height[/tex]

         [tex]=\frac{1}{2}*16*12\\\\=8*12\\\\= 96 m^{2}[/tex]

Triangle 2:

Area2 = [tex]\frac{1}{2}*16*4[/tex]

           = 8 * 4

           = 32 square meter

Area of quadrilateral = 96 + 32 = 128 sq.m

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