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Sagot :
Answer:
Explanation:
You want the area of the output piston not the input piston. The input piston creates a pressure equal to
55.8 N/0.1 m^2 = 558 N/m^2. This pressure is transmitted through the hydraulic fluid and applied to the output piston. The pressure exerted on the output piston is equal to 419 N/Am^2. Set this equal to the applied pressure and solve for A, the area of the output piston.
419/A = 558 , A = 419/558 = 0.751 m^2
Answer:
0.0133 m^2
Explanation:
55.8/419=0.133
0.133*0.100= 0.0133
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