ilehpatience1105
Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Quadratic equation

three years ago a father was three times as old as his son. in five years time, the father will be twice as old as his son.what is the sum of their ages in four years time?​

Sagot :

unicorn3125

Answer:

           46

Step-by-step explanation:

x          -  age of a son three years ago

3x        -  age of a father three years ago

x + 3      -  age of the son now

3x + 3       -  age of the father now

x + 3 + 5       -  age of the son in five years time

3x + 3 + 5       -  age of the father in five years time

in five years time, the father will be twice as old as his son, so:

3x + 3 + 5 = 2(x + 3 + 5)

3x + 8 = 2x + 16

3x - 2x = 16 - 8

  x = 8

x + 3 + 4       -  age of the son in four years time

8 + 3 + 4 = 15

3x + 3 + 4       -  age of the father in four years time

3×8 + 3 + 4 = 31    

the sum of their ages in four years time:

15 + 31 = 46

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.