mxrah
Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Who can help me with these two?!? and can show work plz

Who Can Help Me With These Two And Can Show Work Plz class=

Sagot :

Answer:

(4, 2 ) and (5, - 4 )

Step-by-step explanation:

(3)

6x + 2y = 28 → (1)

x = 2y → (2)

Substitute x = 2y into (1)

6(2y) + 2y = 28

12y + 2y = 28

14y = 28 ( divide both sides by 14 )

y = 2

Substitute y = 2 into (2) for corresponding value of x

x = 2(2) = 4

solution is (4, 2 )

(4)

x + y = 1 → (1)

2x + y = 6 → (2)

Rearrange (2) expressing y in terms of x by subtracting 2x from both sides

y = 6 - 2x → (3)

Substitute y = 6 - 2x into (1)

x + 6 - 2x = 1

- x + 6 = 1 ( subtract 6 from both sides )

- x = - 5 ( multiply both sides by - 1 )

x = 5

Substitute x = 5 into (3) for corresponding value of y

y = 6 - 2(5) = 6 - 10 = - 4

solution is (5, - 4 )