Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

rocket is launched from a tower. The height of the rocket, y in feet, is related to the
time after launch, a in seconds, by the given equation. Using this equation, find out
the time at which the rocket will reach its max, to the nearest 100th of a second.
y=16x^2+ +225x+79

Sagot :

OverpoweredNoob

Answer:

7.03 seconds

Step-by-step explanation:

First, you need to differentiate the equation (The derivative of y represents the rocket's velocity):

y' = 32x + 225

Then, set y' to 0 and solve for x

0 = 32x + 225

x = 7.03s

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.