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Sagot :
Answer:
Step-by-step explanation:
in the rough drawing i've included we want to find the distance of AC and BC and the subtract the shorter from the longer or
BC- AC = AB
does this strategy seem like a good one?
use the mnemonic SOH CAH TOA to remember how sin, cos, and tan, fit on a triangle
SOH Sin = Opp / Hyp
CAH Cos =Adj / Hyp
TOA Tan = Opp / Adj
where Opp = Opposite side, Adj = Adjacent side , and Hyp = Hypotenuse
we are given an angle and the Opposite side so we can use Tan , since that has the thing we want to find, and the things we know.
when AC is the Adj side it's
Tan(60) = 70 / Adj
Adj = 70 / Tan(60)
Adj = 40.4145
Dist. of AC = 40.4145 m
When BC is the Adj side it's
Tan(40) = 70 / Adj
Adj = 70/ Tan(40)
Adj = 83.42275
Dist. of BC = 83.42275
BC - AC = AB
83.45575 - 40.4145 =43.008
to the nearest tenth AB = 43.0 m
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