Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
The relationship in the table represents neither direct variation or inverse variation
Step-by-step explanation:
The table data are;
x = 5, 10, 15, 20
y = 2, 1, 1/3, 1/2
For a direct variation, we have;
y = k × x
Where;
k = A constant
Therefore;
k = y/x = constant for a direct variation
From the data, we have the following y/x values at each data point;
5/2 = 2.5
10/1 = 10
15/(1/3) = 45
20/(1/2) = 40
Therefore, y/x is not constant for the given data, therefore, the relationship in the table is not a direct variation
For an inverse variation, we have;
y·x = k (A constant)
The product of the 'x' and 'y' variables are given as follows;
5 × 2 = 10
10 × 1 = 10
15 × 1/3 = 5
20 × 1/2 = 10
The value of x × y is not always constant, therefore, therefore the relation in the table does not represent an inverse relation
Therefore, the relationship in the table represents neither direct variation or inverse variation
The relation represents an inverse variation because as the values of x is increasing the values of y is decreasing.
y = k/x
5 = k/2
k = 5 x 2 = 10
So here K will be 10.
The given values are in inverse variation and can be represented by equation y = 10/x
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.