Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The polynomial of degree 4, P ( x ) , has a root of multiplicity 2 at x = 1 and roots of multiplicity 1 at x = 0 and x = − 1 . It goes through the point ( 5 , 288 ) .

Sagot :

really226

Answer:

P ( x ) = (3/5)*[(x-1)^2]*(x)*(x + 1 )

Step-by-step explanation:

P ( x ) = a (x-1)^2(x)^1 (x + 1 )^1

sub P(5)=288

288 = a (4)^2(5) (6)

a = 3/5

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.