Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

The polynomial of degree 4, P ( x ) , has a root of multiplicity 2 at x = 1 and roots of multiplicity 1 at x = 0 and x = − 1 . It goes through the point ( 5 , 288 ) .

Sagot :

really226

Answer:

P ( x ) = (3/5)*[(x-1)^2]*(x)*(x + 1 )

Step-by-step explanation:

P ( x ) = a (x-1)^2(x)^1 (x + 1 )^1

sub P(5)=288

288 = a (4)^2(5) (6)

a = 3/5

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.