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Find a10 of the sequence 4, 28, 196, 1372



*Formula: a_n=a_1r^{n-1}a
n
​
=a
1
​
r
n−1

Sagot :

Hrishii

Answer:

[tex] \purple { \bold{ a_{10}=161414428}}[/tex]

Step-by-step explanation:

Given sequence is: 4, 28, 196, 1372

28/4 = 7

196/28 = 7

1372/196 = 7

Since, the ratio of any two consecutive terms is same, so it is a geometric sequence.

Therefore,

Common ratio r = 7

First term a = 4

nth term of a geometric sequence is given as:

[tex]a_n=ar^{n-1} \\ \\\implies \\ \\ a_{10}=4.7^{10-1} \\ \\ a_{10}=4.7^{9} \\ \\ a_{10}=4.7^{9} \\ \\ a_{10}=4(40353607) \\ \\ \red{ \bold{ a_{10}=161414428}}[/tex]

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